Thread: bash: find function and formatting

i trying write bash program uses find function find files in designated folder has more 1 name (ie many links)

code:

find $1 ! -type d -links +2 -ls 2</dev/null

id output formatted line printed out node number followed line has files names. ie

inode1;
name1
name2
inode2;
name1
name2

have no idea how

something this:

code:

find .  ! -type d -links +1 -exec ls -i {} \; | awk '{ if(inode==$1) { print $2 } else { inode=$1; print inode ";"; print $2 }}'

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